PHP
·
发表于 5年以前
·
阅读量：7620
//数组arr1相对于arr2所没有的
const arr1 = [1, 2, 3, 4, 5, 8, 9]
const arr2 = [5, 6, 7, 8, 9];
const diff = arr1.filter(item => !new Set(arr2).has(item))
console.log(diff) //[ 1, 2, 3, 4 ]